TImageEnProc.GetCMYKChannels

Declaration

function GetCMYKChannels(Channel: Integer): TIEBitmap; overload;
procedure GetCMYKChannels(BitmapC, BitmapM, BitmapY, BitmapK: TIEBitmap); overload;

Description

Return a Bitmap with the CMYK specified channel. The result Bitmap is a gray level representation of the specified channel.
Or copies the CMYK channels to separate bitmaps.

Channel is the CMYK channel. You can specify one of the following constants:
Note:
◼If the image PixelFormat is not ie24RGB or ie32RGB, it will be converted
◼You need to free the bitmap returned by GetCMYKChannels()

Demos

Image Testing

// Load test image
ImageEnView1.IO.LoadFromFile( 'D:\TestImage.jpg' );

  

// Return the Cyan channel of the image
bmp1 := ImageEnView1.Proc.GetCMYKChannels( CMYK_C );

  

// Return the Magenta channel of the image
bmp1 := ImageEnView1.Proc.GetCMYKChannels( CMYK_M );

  

// Return the Yellow channel of the image
bmp1 := ImageEnView1.Proc.GetCMYKChannels( CMYK_Y );

  

// Return the Key (black) channel of the image
bmp1 := ImageEnView1.Proc.GetCMYKChannels( CMYK_K );

  

Example

Also see: Automated Samples

// Overload 1 Example
cc := ImageEnView1.Proc.GetCMYKChannels( CMYK_C );
mm := ImageEnView1.Proc.GetCMYKChannels( CMYK_M );
yy := ImageEnView1.Proc.GetCMYKChannels( CMYK_Y );
kk := ImageEnView1.Proc.GetCMYKChannels( CMYK_K );

ImageEnView2.IEBitmap.Assign( cc ); // Copy Cyan channel
ImageEnView3.IEBitmap.Assign( mm ); // Copy Magenta channel
ImageEnView4.IEBitmap.Assign( yy ); // Copy Yellow channel
ImageEnView5.IEBitmap.Assign( kk ); // Copy Black channel

cc.Free;
mm.Free;
yy.Free;
kk.Free;

ImageEnView2.Update();
ImageEnView3.Update();
ImageEnView4.Update();


// Overload 2 Example
ImageEnView1.Proc.GetCMYKChannels( ImageEnView2.IEBitmap, ImageEnView3.IEBitmap, ImageEnView4.IEBitmap, ImageEnView5.IEBitmap );
ImageEnView2.Update();
ImageEnView3.Update();
ImageEnView4.Update();
ImageEnView5.Update();

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