| T O P I C R E V I E W |
| HMArnold |
Posted - Sep 30 2025 : 20:57:15
I'm trying to learn how to select and deselect polygons using TImageEnView
Using this code...
Image.IO.LoadFromFileJpeg('Test.jpg');
SetLength (NodeArry, 4);
NodeArry[0].X := 510; NodeArry[0].Y := 175;
NodeArry[1].X := 570; NodeArry[1].Y := 175;
NodeArry[2].X := 570; NodeArry[2].Y := 270;
NodeArry[3].X := 510; NodeArry[3].Y := 270;
Image.LayersAdd (NodeArry,True,clRed,2,clBlue);
Image.CurrentLayer.Transparency := 75;
Image.CurrentLayer.Tag := 55;
NodeArry[0].X := 485; NodeArry[0].Y := 870;
NodeArry[1].X := 538; NodeArry[1].Y := 870;
NodeArry[2].X := 538; NodeArry[2].Y := 965;
NodeArry[3].X := 485; NodeArry[3].Y := 965;
Image.LayersAdd (NodeArry,True,clRed,2,clBlue);
Image.CurrentLayer.Transparency := 75;
Image.CurrentLayer.Tag := 56;
Image.LayersDeselectAll;
Image.LayersSelectAll(true);
Image.Update;
Both polygons display fine, with the last polygon defined is always selected.
Deselect and SelectAll don't seem to have any effect.
I also don't see a way to select a specific polygon given it's index, handle, or tag
Is there a demo that shows this? If so, I haven't been able to find it
Thanks in advance
HM Arnold |
| 3 L A T E S T R E P L I E S (Newest First) |
| xequte |
Posted - Oct 02 2025 : 01:23:15
Hi
You can get the size and position of the layer using ImageEnView1.Layers[...].PosX/PosY/Width/Height (in terms of bitmap pixels).
You can then use that to add a text layer using the position the overload:
http://www.imageen.com/help/TImageEnView.LayersAdd.html
Or just add the layer then set ImageEnView1.CurrentLayer.PosX/PosY/Width/Height.
See the example at:
http://www.imageen.com/help/TIELayer.PosX.html
Nigel
Xequte Software
www.imageen.com
|
| xequte |
Posted - Oct 02 2025 : 01:19:29
Hi
You can just make the a layer active and selected using LayersCurrent:
ImageEnView1.LayersCurrent := 1;
In a multi-selection scenario, you can use:
http://www.imageen.com/help/TImageEnView.LayersSelectedList.html
or
http://www.imageen.com/help/TImageEnView.Selected.html
Nigel
Xequte Software
www.imageen.com
|
| HMArnold |
Posted - Oct 01 2025 : 10:45:59
Also, what is the new TImageEnView way to add a text label at a pixel X/Y location?
In this case I already have a layer for the polygon.
I assume it is a new layer for each label, but then how do I locate it to a pixel coordinate near the polygon?
I can't find a Demo or Help section that describes setting the text location
HM Arnold |
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