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 How to calculate Opacity properly		  New Topic  Reply to Topic
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yogiyang

India
728 Posts
Posted - Jan 04 2014 :  08:28:58  Show Profile  Reply
Hello,

I am attaching an image with this post which contains a few layers whose Opacity is set at 99 but ImageEn reports 0.988235294117647 (Layer 1 & 4)

In the same way if the Opacity is set at 98 ImageEn reports 0.980392156862745 (Layer 6)

Again Opacity 91 is reported as 0.909803921568627 (Layer 3)

Now trying to multiply above value by 100 would give me 98 in case of Layer 1, 4 & 9.

How to get the exact value of 99 and 99?

TIA

Yogi Yang

Download Attachment: 20141482733_SampleImage_008.zip

w2m

USA
1990 Posts
Posted - Jan 04 2014 :  09:03:15  Show Profile  Reply 
var
iLayerOpacity: double;
iLayerOpacityString: string;
iLayerOpacity := ImageEnView.Layers[i].Opacity * 100;
iLayerOpacityString := FormatFloat('0',iLayerOpacity); //show 98
... or ...
iLayerOpacityString := FormatFloat('###',iLayerOpacity); //show 98

William Miller
Adirondack Software & Graphics
Email: w2m@frontiernet.net
EBook: http://www.imageen.com/ebook/
Apprehend: http://www.frontiernet.net/~w2m/index.html
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yogiyang

India
728 Posts
Posted - Jan 04 2014 :  23:14:10  Show Profile  Reply
William,

Thanks for the suggestion.

I think I have found a solution to this problem.

Round(Layers[I].Opacity * 100)


If you feel this is wrong please do correct me.

Regards,


Yogi Yang
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